To add a map dynamically to a list in Groovy, you can simply create a new map and then add it to the list using the add() method.
For example:
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def list = [] def map = [key1: 'value1', key2: 'value2'] list.add(map) |
This will add the map {key1: 'value1', key2: 'value2'} to the list list. You can repeat this process for adding multiple maps dynamically to the list.
How to remove a map from a list dynamically in Groovy?
You can remove a map from a list dynamically in Groovy using the remove() method. Here's an example:
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def list = [ [name: 'Alice', age: 30], [name: 'Bob', age: 25], [name: 'Charlie', age: 35] ] def mapToRemove = [name: 'Bob', age: 25] list.remove(mapToRemove) println list |
In this example, we have a list of maps and we want to remove the map with the name 'Bob' and age 25. We use the remove() method on the list and pass in the map we want to remove. After removing the map, we print out the updated list.
How do I dynamically insert a map into a list in Groovy?
You can dynamically insert a map into a list in Groovy by using the add() method of the list. Here is an example:
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def listOfMaps = [] def map = [key1: 'value1', key2: 'value2'] listOfMaps.add(map) println listOfMaps |
In this example, we create an empty list listOfMaps and a map map. We then use the add() method to insert the map into the list. Finally, we print the listOfMaps to verify that the map has been successfully inserted into the list.
How to dynamically add a map to a list in Groovy?
To dynamically add a map to a list in Groovy, you can simply use the add method of the list object. Here is an example:
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// Create an empty list def list = [] // Create a map def map = [key1: 'value1', key2: 'value2'] // Add the map to the list list.add(map) // Print the list println list |
In this example, we first create an empty list list. Next, we create a map map with key-value pairs. Finally, we use the add method to add the map to the list. The println statement is used to print the list, which will show the map that was added to it.
